Optimal. Leaf size=270 \[ -\frac {\sqrt {2 x+1} (5-4 x)}{31 \left (5 x^2+3 x+2\right )}-\frac {1}{31} \sqrt {\frac {1}{310} \left (47 \sqrt {35}-218\right )} \log \left (5 (2 x+1)-\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {2 x+1}+\sqrt {35}\right )+\frac {1}{31} \sqrt {\frac {1}{310} \left (47 \sqrt {35}-218\right )} \log \left (5 (2 x+1)+\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {2 x+1}+\sqrt {35}\right )-\frac {1}{31} \sqrt {\frac {2}{155} \left (218+47 \sqrt {35}\right )} \tan ^{-1}\left (\frac {\sqrt {10 \left (2+\sqrt {35}\right )}-10 \sqrt {2 x+1}}{\sqrt {10 \left (\sqrt {35}-2\right )}}\right )+\frac {1}{31} \sqrt {\frac {2}{155} \left (218+47 \sqrt {35}\right )} \tan ^{-1}\left (\frac {10 \sqrt {2 x+1}+\sqrt {10 \left (2+\sqrt {35}\right )}}{\sqrt {10 \left (\sqrt {35}-2\right )}}\right ) \]
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Rubi [A] time = 0.36, antiderivative size = 270, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 7, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.318, Rules used = {738, 826, 1169, 634, 618, 204, 628} \[ -\frac {\sqrt {2 x+1} (5-4 x)}{31 \left (5 x^2+3 x+2\right )}-\frac {1}{31} \sqrt {\frac {1}{310} \left (47 \sqrt {35}-218\right )} \log \left (5 (2 x+1)-\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {2 x+1}+\sqrt {35}\right )+\frac {1}{31} \sqrt {\frac {1}{310} \left (47 \sqrt {35}-218\right )} \log \left (5 (2 x+1)+\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {2 x+1}+\sqrt {35}\right )-\frac {1}{31} \sqrt {\frac {2}{155} \left (218+47 \sqrt {35}\right )} \tan ^{-1}\left (\frac {\sqrt {10 \left (2+\sqrt {35}\right )}-10 \sqrt {2 x+1}}{\sqrt {10 \left (\sqrt {35}-2\right )}}\right )+\frac {1}{31} \sqrt {\frac {2}{155} \left (218+47 \sqrt {35}\right )} \tan ^{-1}\left (\frac {10 \sqrt {2 x+1}+\sqrt {10 \left (2+\sqrt {35}\right )}}{\sqrt {10 \left (\sqrt {35}-2\right )}}\right ) \]
Antiderivative was successfully verified.
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Rule 204
Rule 618
Rule 628
Rule 634
Rule 738
Rule 826
Rule 1169
Rubi steps
\begin {align*} \int \frac {(1+2 x)^{3/2}}{\left (2+3 x+5 x^2\right )^2} \, dx &=-\frac {(5-4 x) \sqrt {1+2 x}}{31 \left (2+3 x+5 x^2\right )}+\frac {1}{31} \int \frac {9+4 x}{\sqrt {1+2 x} \left (2+3 x+5 x^2\right )} \, dx\\ &=-\frac {(5-4 x) \sqrt {1+2 x}}{31 \left (2+3 x+5 x^2\right )}+\frac {2}{31} \operatorname {Subst}\left (\int \frac {14+4 x^2}{7-4 x^2+5 x^4} \, dx,x,\sqrt {1+2 x}\right )\\ &=-\frac {(5-4 x) \sqrt {1+2 x}}{31 \left (2+3 x+5 x^2\right )}+\frac {\operatorname {Subst}\left (\int \frac {14 \sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )}-\left (14-4 \sqrt {\frac {7}{5}}\right ) x}{\sqrt {\frac {7}{5}}-\sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )} x+x^2} \, dx,x,\sqrt {1+2 x}\right )}{31 \sqrt {14 \left (2+\sqrt {35}\right )}}+\frac {\operatorname {Subst}\left (\int \frac {14 \sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )}+\left (14-4 \sqrt {\frac {7}{5}}\right ) x}{\sqrt {\frac {7}{5}}+\sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )} x+x^2} \, dx,x,\sqrt {1+2 x}\right )}{31 \sqrt {14 \left (2+\sqrt {35}\right )}}\\ &=-\frac {(5-4 x) \sqrt {1+2 x}}{31 \left (2+3 x+5 x^2\right )}+\frac {1}{155} \left (2+\sqrt {35}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {\frac {7}{5}}-\sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )} x+x^2} \, dx,x,\sqrt {1+2 x}\right )+\frac {1}{155} \left (2+\sqrt {35}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {\frac {7}{5}}+\sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )} x+x^2} \, dx,x,\sqrt {1+2 x}\right )-\frac {1}{31} \sqrt {\frac {1}{310} \left (-218+47 \sqrt {35}\right )} \operatorname {Subst}\left (\int \frac {-\sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )}+2 x}{\sqrt {\frac {7}{5}}-\sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )} x+x^2} \, dx,x,\sqrt {1+2 x}\right )+\frac {1}{31} \sqrt {\frac {1}{310} \left (-218+47 \sqrt {35}\right )} \operatorname {Subst}\left (\int \frac {\sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )}+2 x}{\sqrt {\frac {7}{5}}+\sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )} x+x^2} \, dx,x,\sqrt {1+2 x}\right )\\ &=-\frac {(5-4 x) \sqrt {1+2 x}}{31 \left (2+3 x+5 x^2\right )}-\frac {1}{31} \sqrt {\frac {1}{310} \left (-218+47 \sqrt {35}\right )} \log \left (\sqrt {35}-\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {1+2 x}+5 (1+2 x)\right )+\frac {1}{31} \sqrt {\frac {1}{310} \left (-218+47 \sqrt {35}\right )} \log \left (\sqrt {35}+\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {1+2 x}+5 (1+2 x)\right )-\frac {1}{155} \left (2 \left (2+\sqrt {35}\right )\right ) \operatorname {Subst}\left (\int \frac {1}{\frac {2}{5} \left (2-\sqrt {35}\right )-x^2} \, dx,x,-\sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )}+2 \sqrt {1+2 x}\right )-\frac {1}{155} \left (2 \left (2+\sqrt {35}\right )\right ) \operatorname {Subst}\left (\int \frac {1}{\frac {2}{5} \left (2-\sqrt {35}\right )-x^2} \, dx,x,\sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )}+2 \sqrt {1+2 x}\right )\\ &=-\frac {(5-4 x) \sqrt {1+2 x}}{31 \left (2+3 x+5 x^2\right )}-\frac {1}{31} \sqrt {\frac {2}{155} \left (218+47 \sqrt {35}\right )} \tan ^{-1}\left (\sqrt {\frac {5}{2 \left (-2+\sqrt {35}\right )}} \left (\sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )}-2 \sqrt {1+2 x}\right )\right )+\frac {1}{31} \sqrt {\frac {2}{155} \left (218+47 \sqrt {35}\right )} \tan ^{-1}\left (\sqrt {\frac {5}{2 \left (-2+\sqrt {35}\right )}} \left (\sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )}+2 \sqrt {1+2 x}\right )\right )-\frac {1}{31} \sqrt {\frac {1}{310} \left (-218+47 \sqrt {35}\right )} \log \left (\sqrt {35}-\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {1+2 x}+5 (1+2 x)\right )+\frac {1}{31} \sqrt {\frac {1}{310} \left (-218+47 \sqrt {35}\right )} \log \left (\sqrt {35}+\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {1+2 x}+5 (1+2 x)\right )\\ \end {align*}
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Mathematica [C] time = 0.71, size = 141, normalized size = 0.52 \[ \frac {\frac {155 \sqrt {2 x+1} (4 x-5)}{5 x^2+3 x+2}+2 \left (31-4 i \sqrt {31}\right ) \sqrt {10-5 i \sqrt {31}} \tanh ^{-1}\left (\frac {\sqrt {10 x+5}}{\sqrt {2-i \sqrt {31}}}\right )+2 \left (31+4 i \sqrt {31}\right ) \sqrt {10+5 i \sqrt {31}} \tanh ^{-1}\left (\frac {\sqrt {10 x+5}}{\sqrt {2+i \sqrt {31}}}\right )}{4805} \]
Antiderivative was successfully verified.
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fricas [B] time = 0.78, size = 538, normalized size = 1.99 \[ -\frac {3844 \cdot 77315^{\frac {1}{4}} \sqrt {155} \sqrt {35} {\left (5 \, x^{2} + 3 \, x + 2\right )} \sqrt {20492 \, \sqrt {35} + 154630} \arctan \left (\frac {1}{3788913966425} \cdot 77315^{\frac {3}{4}} \sqrt {155} \sqrt {47} \sqrt {77315^{\frac {1}{4}} \sqrt {155} {\left (2 \, \sqrt {35} \sqrt {31} - 35 \, \sqrt {31}\right )} \sqrt {2 \, x + 1} \sqrt {20492 \, \sqrt {35} + 154630} + 15808450 \, x + 1580845 \, \sqrt {35} + 7904225} {\left (\sqrt {35} \sqrt {7} - 2 \, \sqrt {7}\right )} \sqrt {20492 \, \sqrt {35} + 154630} - \frac {1}{74299715} \cdot 77315^{\frac {3}{4}} \sqrt {155} \sqrt {2 \, x + 1} \sqrt {20492 \, \sqrt {35} + 154630} {\left (\sqrt {35} - 2\right )} + \frac {1}{31} \, \sqrt {35} \sqrt {31} + \frac {2}{31} \, \sqrt {31}\right ) + 3844 \cdot 77315^{\frac {1}{4}} \sqrt {155} \sqrt {35} {\left (5 \, x^{2} + 3 \, x + 2\right )} \sqrt {20492 \, \sqrt {35} + 154630} \arctan \left (\frac {1}{7577827932850} \cdot 77315^{\frac {3}{4}} \sqrt {155} \sqrt {-188 \cdot 77315^{\frac {1}{4}} \sqrt {155} {\left (2 \, \sqrt {35} \sqrt {31} - 35 \, \sqrt {31}\right )} \sqrt {2 \, x + 1} \sqrt {20492 \, \sqrt {35} + 154630} + 2971988600 \, x + 297198860 \, \sqrt {35} + 1485994300} {\left (\sqrt {35} \sqrt {7} - 2 \, \sqrt {7}\right )} \sqrt {20492 \, \sqrt {35} + 154630} - \frac {1}{74299715} \cdot 77315^{\frac {3}{4}} \sqrt {155} \sqrt {2 \, x + 1} \sqrt {20492 \, \sqrt {35} + 154630} {\left (\sqrt {35} - 2\right )} - \frac {1}{31} \, \sqrt {35} \sqrt {31} - \frac {2}{31} \, \sqrt {31}\right ) - 77315^{\frac {1}{4}} \sqrt {155} {\left (218 \, \sqrt {35} \sqrt {31} {\left (5 \, x^{2} + 3 \, x + 2\right )} - 1645 \, \sqrt {31} {\left (5 \, x^{2} + 3 \, x + 2\right )}\right )} \sqrt {20492 \, \sqrt {35} + 154630} \log \left (\frac {188}{7} \cdot 77315^{\frac {1}{4}} \sqrt {155} {\left (2 \, \sqrt {35} \sqrt {31} - 35 \, \sqrt {31}\right )} \sqrt {2 \, x + 1} \sqrt {20492 \, \sqrt {35} + 154630} + 424569800 \, x + 42456980 \, \sqrt {35} + 212284900\right ) + 77315^{\frac {1}{4}} \sqrt {155} {\left (218 \, \sqrt {35} \sqrt {31} {\left (5 \, x^{2} + 3 \, x + 2\right )} - 1645 \, \sqrt {31} {\left (5 \, x^{2} + 3 \, x + 2\right )}\right )} \sqrt {20492 \, \sqrt {35} + 154630} \log \left (-\frac {188}{7} \cdot 77315^{\frac {1}{4}} \sqrt {155} {\left (2 \, \sqrt {35} \sqrt {31} - 35 \, \sqrt {31}\right )} \sqrt {2 \, x + 1} \sqrt {20492 \, \sqrt {35} + 154630} + 424569800 \, x + 42456980 \, \sqrt {35} + 212284900\right ) - 490061950 \, {\left (4 \, x - 5\right )} \sqrt {2 \, x + 1}}{15191920450 \, {\left (5 \, x^{2} + 3 \, x + 2\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 1.32, size = 622, normalized size = 2.30 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.29, size = 642, normalized size = 2.38 \[ -\frac {39 \left (2 \sqrt {5}\, \sqrt {7}+4\right ) \arctan \left (\frac {-\sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}+10 \sqrt {2 x +1}}{\sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\right )}{961 \sqrt {10 \sqrt {5}\, \sqrt {7}-20}}+\frac {4 \sqrt {5}\, \left (2 \sqrt {5}\, \sqrt {7}+4\right ) \sqrt {7}\, \arctan \left (\frac {-\sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}+10 \sqrt {2 x +1}}{\sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\right )}{961 \sqrt {10 \sqrt {5}\, \sqrt {7}-20}}+\frac {4 \sqrt {5}\, \sqrt {7}\, \arctan \left (\frac {-\sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}+10 \sqrt {2 x +1}}{\sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\right )}{31 \sqrt {10 \sqrt {5}\, \sqrt {7}-20}}-\frac {39 \left (2 \sqrt {5}\, \sqrt {7}+4\right ) \arctan \left (\frac {\sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}+10 \sqrt {2 x +1}}{\sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\right )}{961 \sqrt {10 \sqrt {5}\, \sqrt {7}-20}}+\frac {4 \sqrt {5}\, \left (2 \sqrt {5}\, \sqrt {7}+4\right ) \sqrt {7}\, \arctan \left (\frac {\sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}+10 \sqrt {2 x +1}}{\sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\right )}{961 \sqrt {10 \sqrt {5}\, \sqrt {7}-20}}+\frac {4 \sqrt {5}\, \sqrt {7}\, \arctan \left (\frac {\sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}+10 \sqrt {2 x +1}}{\sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\right )}{31 \sqrt {10 \sqrt {5}\, \sqrt {7}-20}}-\frac {39 \sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \ln \left (10 x +\sqrt {5}\, \sqrt {7}-\sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \sqrt {5}\, \sqrt {2 x +1}+5\right )}{9610}+\frac {2 \sqrt {7}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \ln \left (10 x +\sqrt {5}\, \sqrt {7}-\sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \sqrt {5}\, \sqrt {2 x +1}+5\right )}{961}+\frac {39 \sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \ln \left (10 x +\sqrt {5}\, \sqrt {7}+\sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \sqrt {5}\, \sqrt {2 x +1}+5\right )}{9610}-\frac {2 \sqrt {7}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \ln \left (10 x +\sqrt {5}\, \sqrt {7}+\sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \sqrt {5}\, \sqrt {2 x +1}+5\right )}{961}+\frac {\frac {8 \left (2 x +1\right )^{\frac {3}{2}}}{155}-\frac {28 \sqrt {2 x +1}}{155}}{-\frac {8 x}{5}+\left (2 x +1\right )^{2}+\frac {3}{5}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (2 \, x + 1\right )}^{\frac {3}{2}}}{{\left (5 \, x^{2} + 3 \, x + 2\right )}^{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 1.04, size = 208, normalized size = 0.77 \[ -\frac {\frac {28\,\sqrt {2\,x+1}}{155}-\frac {8\,{\left (2\,x+1\right )}^{3/2}}{155}}{{\left (2\,x+1\right )}^2-\frac {8\,x}{5}+\frac {3}{5}}+\frac {\sqrt {155}\,\mathrm {atan}\left (\frac {\sqrt {155}\,\sqrt {-218-\sqrt {31}\,31{}\mathrm {i}}\,\sqrt {2\,x+1}\,128{}\mathrm {i}}{3003125\,\left (\frac {3584}{600625}+\frac {\sqrt {31}\,896{}\mathrm {i}}{600625}\right )}+\frac {256\,\sqrt {31}\,\sqrt {155}\,\sqrt {-218-\sqrt {31}\,31{}\mathrm {i}}\,\sqrt {2\,x+1}}{93096875\,\left (\frac {3584}{600625}+\frac {\sqrt {31}\,896{}\mathrm {i}}{600625}\right )}\right )\,\sqrt {-218-\sqrt {31}\,31{}\mathrm {i}}\,2{}\mathrm {i}}{4805}-\frac {\sqrt {155}\,\mathrm {atan}\left (\frac {\sqrt {155}\,\sqrt {-218+\sqrt {31}\,31{}\mathrm {i}}\,\sqrt {2\,x+1}\,128{}\mathrm {i}}{3003125\,\left (-\frac {3584}{600625}+\frac {\sqrt {31}\,896{}\mathrm {i}}{600625}\right )}-\frac {256\,\sqrt {31}\,\sqrt {155}\,\sqrt {-218+\sqrt {31}\,31{}\mathrm {i}}\,\sqrt {2\,x+1}}{93096875\,\left (-\frac {3584}{600625}+\frac {\sqrt {31}\,896{}\mathrm {i}}{600625}\right )}\right )\,\sqrt {-218+\sqrt {31}\,31{}\mathrm {i}}\,2{}\mathrm {i}}{4805} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 111.05, size = 248, normalized size = 0.92 \[ \frac {320 \left (2 x + 1\right )^{\frac {3}{2}}}{- 4960 x + 3100 \left (2 x + 1\right )^{2} + 1860} - \frac {1120 \left (2 x + 1\right )^{\frac {3}{2}}}{- 34720 x + 21700 \left (2 x + 1\right )^{2} + 13020} - \frac {128 \sqrt {2 x + 1}}{- 4960 x + 3100 \left (2 x + 1\right )^{2} + 1860} - \frac {3024 \sqrt {2 x + 1}}{- 34720 x + 21700 \left (2 x + 1\right )^{2} + 13020} + 16 \operatorname {RootSum} {\left (407144088666112 t^{4} + 3325152256 t^{2} + 11045, \left (t \mapsto t \log {\left (\frac {33312534528 t^{3}}{235} + \frac {166784 t}{235} + \sqrt {2 x + 1} \right )} \right )\right )} - \frac {112 \operatorname {RootSum} {\left (19950060344639488 t^{4} + 498437272576 t^{2} + 10878125, \left (t \mapsto t \log {\left (- \frac {11049511452672 t^{3}}{2205125} + \frac {307918256 t}{2205125} + \sqrt {2 x + 1} \right )} \right )\right )}}{5} - \frac {16 \operatorname {RootSum} {\left (407144088666112 t^{4} + 3325152256 t^{2} + 11045, \left (t \mapsto t \log {\left (\frac {33312534528 t^{3}}{235} + \frac {166784 t}{235} + \sqrt {2 x + 1} \right )} \right )\right )}}{5} + \frac {16 \operatorname {RootSum} {\left (1722112 t^{4} + 1984 t^{2} + 5, \left (t \mapsto t \log {\left (- \frac {27776 t^{3}}{5} + \frac {108 t}{5} + \sqrt {2 x + 1} \right )} \right )\right )}}{5} \]
Verification of antiderivative is not currently implemented for this CAS.
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